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    1. 明輝手游網中心:是一個免費提供流行視頻軟件教程、在線學習分享的學習平臺!

      一套加解密字符串的函數

      [摘要]<%Function Encrypt(theNumber)On Error Resume NextDim n, szEnc, t, HiN, LoN, in = CDbl((theNumber...
      <%
      Function Encrypt(theNumber)
      On Error Resume Next
      Dim n, szEnc, t, HiN, LoN, i
      n = CDbl((theNumber + 1570) ^ 2 - 7 * (theNumber + 1570) - 450)
      If n < 0 Then szEnc = "R" Else szEnc = "J"
      n = CStr(abs(n))
      For i = 1 To Len(n) step 2
      t = Mid(n, i, 2)
      If Len(t) = 1 Then
      szEnc = szEnc & t
      Exit For
      End If
      HiN = (CInt(t) And 240) / 16
      LoN = CInt(t) And 15
      szEnc = szEnc & Chr(Asc("M") + HiN) & Chr(Asc("C") + LoN)
      Next
      Encrypt = szEnc
      End Function

      Function Decrypt(theNumber)
      On Error Resume Next
      Dim e, n, sign, t, HiN, LoN, NewN, i
      e = theNumber
      If Left(e, 1) = "R" Then sign = -1 Else sign = 1
      e = Mid(e, 2)
      NewN = ""
      For i = 1 To Len(e) step 2
      t = Mid(e, i, 2)
      If Asc(t) >= Asc("0") And Asc(t) <= Asc("9") Then
      NewN = NewN & t
      Exit For
      End If
      HiN = Mid(t, 1, 1)
      LoN = Mid(t, 2, 1)
      HiN = (Asc(HiN) - Asc("M")) * 16
      LoN = Asc(LoN) - Asc("C")
      t = CStr(HiN Or LoN)
      If Len(t) = 1 Then t = "0" & t
      NewN = NewN & t
      Next
      e = CDbl(NewN) * sign
      Decrypt = CLng((7 + sqr(49 - 4 * (-450 - e))) / 2 - 1570)
      End Function
      %>
      <html><body>
      Original number: 69 <br>
      Encrypt(69) returns: JNMQMOJ8 <br>
      Decrypt("JNMQMOJ8") returns: 69
      <p>
      Another example using variables instead: <br>
      Encrypt(Request.Form("ID")) <br>
      Encrypt(myVar) <br>
      Decrypt(Request.QueryString("id")) <br>
      Decrypt("JNMQMOJ8") <br>
      Decrypt(myVar)

      </body></html>





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